When registering an ancillary SPI device, the current code flags a chip
select conflict with the parent device. This happens because the
ancillary device intentionally uses one of the parent's chip selects,
but __spi_add_device() checks against all existing devices including
the parent.
Allow this by passing the parent device pointer to __spi_add_device()
and skipping the conflict check when the existing device is the parent.
Signed-off-by: Antoniu Miclaus <antoniu.miclaus@analog.com>
---
drivers/spi/spi.c | 29 +++++++++++++++++++++++------
1 file changed, 23 insertions(+), 6 deletions(-)
diff --git a/drivers/spi/spi.c b/drivers/spi/spi.c
index e25df9990f82..18ca3c7bad6b 100644
--- a/drivers/spi/spi.c
+++ b/drivers/spi/spi.c
@@ -641,12 +641,26 @@ static inline int spi_dev_check_cs(struct device *dev,
return 0;
}
+struct spi_dev_check_info {
+ struct spi_device *new_spi;
+ struct spi_device *parent; /* set for ancillary devices */
+};
+
static int spi_dev_check(struct device *dev, void *data)
{
struct spi_device *spi = to_spi_device(dev);
- struct spi_device *new_spi = data;
+ struct spi_dev_check_info *info = data;
+ struct spi_device *new_spi = info->new_spi;
int status, idx;
+ /*
+ * When registering an ancillary device, skip checking against the
+ * parent device since the ancillary is intentionally using one of
+ * the parent's chip selects.
+ */
+ if (info->parent && spi == info->parent)
+ return 0;
+
if (spi->controller == new_spi->controller) {
for (idx = 0; idx < spi->num_chipselect; idx++) {
status = spi_dev_check_cs(dev, spi, idx, new_spi, 0);
@@ -663,10 +677,11 @@ static void spi_cleanup(struct spi_device *spi)
spi->controller->cleanup(spi);
}
-static int __spi_add_device(struct spi_device *spi)
+static int __spi_add_device(struct spi_device *spi, struct spi_device *parent)
{
struct spi_controller *ctlr = spi->controller;
struct device *dev = ctlr->dev.parent;
+ struct spi_dev_check_info check_info;
int status, idx;
u8 cs;
@@ -710,7 +725,9 @@ static int __spi_add_device(struct spi_device *spi)
* chipselect **BEFORE** we call setup(), else we'll trash
* its configuration.
*/
- status = bus_for_each_dev(&spi_bus_type, NULL, spi, spi_dev_check);
+ check_info.new_spi = spi;
+ check_info.parent = parent;
+ status = bus_for_each_dev(&spi_bus_type, NULL, &check_info, spi_dev_check);
if (status)
return status;
@@ -772,7 +789,7 @@ int spi_add_device(struct spi_device *spi)
spi_dev_set_name(spi);
mutex_lock(&ctlr->add_lock);
- status = __spi_add_device(spi);
+ status = __spi_add_device(spi, NULL);
mutex_unlock(&ctlr->add_lock);
return status;
}
@@ -2580,8 +2597,8 @@ struct spi_device *spi_new_ancillary_device(struct spi_device *spi,
WARN_ON(!mutex_is_locked(&ctlr->add_lock));
- /* Register the new device */
- rc = __spi_add_device(ancillary);
+ /* Register the new device, passing the parent to skip CS conflict check */
+ rc = __spi_add_device(ancillary, spi);
if (rc) {
dev_err(&spi->dev, "failed to register ancillary device\n");
goto err_out;
--
2.43.0
On 2/6/26 10:07 AM, Antoniu Miclaus wrote:
> When registering an ancillary SPI device, the current code flags a chip
> select conflict with the parent device. This happens because the
> ancillary device intentionally uses one of the parent's chip selects,
> but __spi_add_device() checks against all existing devices including
> the parent.
>
> Allow this by passing the parent device pointer to __spi_add_device()
> and skipping the conflict check when the existing device is the parent.
>
...
> static int spi_dev_check(struct device *dev, void *data)
> {
> struct spi_device *spi = to_spi_device(dev);
> - struct spi_device *new_spi = data;
> + struct spi_dev_check_info *info = data;
> + struct spi_device *new_spi = info->new_spi;
> int status, idx;
>
> + /*
> + * When registering an ancillary device, skip checking against the
> + * parent device since the ancillary is intentionally using one of
> + * the parent's chip selects.
> + */
> + if (info->parent && spi == info->parent)
spi should never be NULL (or we would get a segfault later), so
if `(spi == info->parent)` should be enough.
> + return 0;
> +
Reviewed-by: David Lechner <dlechner@baylibre.com>
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