Use the existing CPUCFG6_PMNUM_SHIFT macro definition instead of
the magic value 4 to get the PMU number.
Signed-off-by: Tiezhu Yang <yangtiezhu@loongson.cn>
---
arch/loongarch/kernel/perf_event.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/arch/loongarch/kernel/perf_event.c b/arch/loongarch/kernel/perf_event.c
index 8ad098703488..2d0c14bdadda 100644
--- a/arch/loongarch/kernel/perf_event.c
+++ b/arch/loongarch/kernel/perf_event.c
@@ -851,7 +851,7 @@ static int __init init_hw_perf_events(void)
return -ENODEV;
pr_info("Performance counters: ");
- counters = ((read_cpucfg(LOONGARCH_CPUCFG6) & CPUCFG6_PMNUM) >> 4) + 1;
+ counters = ((read_cpucfg(LOONGARCH_CPUCFG6) & CPUCFG6_PMNUM) >> CPUCFG6_PMNUM_SHIFT) + 1;
loongarch_pmu.num_counters = counters;
loongarch_pmu.max_period = (1ULL << 63) - 1;
--
2.42.0