We completely clean and restore root domains bandwidth accounting after
every root domains change, so the dl_clear_root_domain() call in
partition_sched_domains_locked() is redundant.
Remove it.
Reviewed-by: Waiman Long <llong@redhat.com>
Reviewed-by: Shrikanth Hegde <sshegde@linux.ibm.com>
Tested-by: Waiman Long <longman@redhat.com>
Tested-by: Jon Hunter <jonathanh@nvidia.com>
Signed-off-by: Juri Lelli <juri.lelli@redhat.com>
---
kernel/sched/topology.c | 15 +--------------
1 file changed, 1 insertion(+), 14 deletions(-)
diff --git a/kernel/sched/topology.c b/kernel/sched/topology.c
index 363ad268a25b..df2d94a57e84 100644
--- a/kernel/sched/topology.c
+++ b/kernel/sched/topology.c
@@ -2720,21 +2720,8 @@ void partition_sched_domains_locked(int ndoms_new, cpumask_var_t doms_new[],
for (i = 0; i < ndoms_cur; i++) {
for (j = 0; j < n && !new_topology; j++) {
if (cpumask_equal(doms_cur[i], doms_new[j]) &&
- dattrs_equal(dattr_cur, i, dattr_new, j)) {
- struct root_domain *rd;
-
- /*
- * This domain won't be destroyed and as such
- * its dl_bw->total_bw needs to be cleared.
- * Tasks contribution will be then recomputed
- * in function dl_update_tasks_root_domain(),
- * dl_servers contribution in function
- * dl_restore_server_root_domain().
- */
- rd = cpu_rq(cpumask_any(doms_cur[i]))->rd;
- dl_clear_root_domain(rd);
+ dattrs_equal(dattr_cur, i, dattr_new, j))
goto match1;
- }
}
/* No match - a current sched domain not in new doms_new[] */
detach_destroy_domains(doms_cur[i]);
--
2.48.1