evsel__is_hybrid returns true if there are multiple core PMUs and the
evsel is for a core PMU. Determining the number of core PMUs can
require loading/scanning PMUs. There's no point doing the scanning if
evsel for the is_hybrid test isn't core so reorder the tests to reduce
PMU scanning.

Signed-off-by: Ian Rogers <irogers@google.com>
---
 tools/perf/util/evsel.c | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/tools/perf/util/evsel.c b/tools/perf/util/evsel.c
index bc144388f892..ae20691bbfae 100644
--- a/tools/perf/util/evsel.c
+++ b/tools/perf/util/evsel.c
@@ -3856,10 +3856,10 @@ void evsel__zero_per_pkg(struct evsel *evsel)
  */
 bool evsel__is_hybrid(const struct evsel *evsel)
 {
-	if (perf_pmus__num_core_pmus() == 1)
+	if (!evsel->core.is_pmu_core)
 		return false;
 
-	return evsel->core.is_pmu_core;
+	return perf_pmus__num_core_pmus() > 1;
 }
 
 struct evsel *evsel__leader(const struct evsel *evsel)
-- 
2.48.0.rc2.279.g1de40edade-goog