There is only one job when running "make JOBS=1", it should
print "sequential build" rather than "parallel build".

Before:

$ cd tools/perf && make JOBS=1
  BUILD:   Doing 'make -j1' parallel build

After:

$ cd tools/perf && make JOBS=1
  BUILD:   Doing 'make -j1' sequential build

Signed-off-by: Tiezhu Yang <yangtiezhu@loongson.cn>
---
 tools/perf/Makefile | 8 +++++++-
 1 file changed, 7 insertions(+), 1 deletion(-)

diff --git a/tools/perf/Makefile b/tools/perf/Makefile
index 75f3f6e0a231..816d5d84816b 100644
--- a/tools/perf/Makefile
+++ b/tools/perf/Makefile
@@ -51,8 +51,14 @@ else
   override DEBUG = 0
 endif
 
+ifeq ($(JOBS),1)
+  BUILD_TYPE := sequential
+else
+  BUILD_TYPE := parallel
+endif
+
 define print_msg
-  @printf '  BUILD:   Doing '\''make \033[33m-j'$(JOBS)'\033[m'\'' parallel build\n'
+  @printf '  BUILD:   Doing '\''make \033[33m-j'$(JOBS)'\033[m'\'' $(BUILD_TYPE) build\n'
 endef
 
 define make
-- 
2.42.0