From: Guenter Roeck <linux@roeck-us.net>

If a chip only provides a single regulator, it should be named 'vout'
and not 'vout0'. Declare regulator using PMBUS_REGULATOR_ONE() to make
that happen.

Cc: Conor Dooley <conor@kernel.org>
Cc: Naresh Solanki <naresh.solanki@9elements.com>
Cc: Patrick Rudolph <patrick.rudolph@9elements.com>
Signed-off-by: Guenter Roeck <linux@roeck-us.net>
Signed-off-by: Conor Dooley <conor.dooley@microchip.com>
---
 drivers/hwmon/pmbus/ir38064.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/drivers/hwmon/pmbus/ir38064.c b/drivers/hwmon/pmbus/ir38064.c
index 04185be3fdb6..69e18cb468f6 100644
--- a/drivers/hwmon/pmbus/ir38064.c
+++ b/drivers/hwmon/pmbus/ir38064.c
@@ -22,7 +22,7 @@
 
 #if IS_ENABLED(CONFIG_SENSORS_IR38064_REGULATOR)
 static const struct regulator_desc ir38064_reg_desc[] = {
-	PMBUS_REGULATOR("vout", 0),
+	PMBUS_REGULATOR_ONE("vout"),
 };
 #endif /* CONFIG_SENSORS_IR38064_REGULATOR */
 
-- 
2.43.0