This is normally done by the generic entry code, but the
kernel_stack_overflow() flow bypasses it.

Reviewed-by: Alexander Potapenko <glider@google.com>
Signed-off-by: Ilya Leoshkevich <iii@linux.ibm.com>
---
 arch/s390/kernel/traps.c | 6 ++++++
 1 file changed, 6 insertions(+)

diff --git a/arch/s390/kernel/traps.c b/arch/s390/kernel/traps.c
index 1d2aa448d103..f299b1203a20 100644
--- a/arch/s390/kernel/traps.c
+++ b/arch/s390/kernel/traps.c
@@ -27,6 +27,7 @@
 #include <linux/uaccess.h>
 #include <linux/cpu.h>
 #include <linux/entry-common.h>
+#include <linux/kmsan.h>
 #include <asm/asm-extable.h>
 #include <asm/fpu/api.h>
 #include <asm/vtime.h>
@@ -260,6 +261,11 @@ static void monitor_event_exception(struct pt_regs *regs)
 
 void kernel_stack_overflow(struct pt_regs *regs)
 {
+	/*
+	 * Normally regs are unpoisoned by the generic entry code, but
+	 * kernel_stack_overflow() is a rare case that is called bypassing it.
+	 */
+	kmsan_unpoison_entry_regs(regs);
 	bust_spinlocks(1);
 	printk("Kernel stack overflow.\n");
 	show_regs(regs);
-- 
2.41.0