Since MULTU opcodes don't record the most significant bits
of the infinite result, sign-extending the sources make no
difference in the result.

Once we remove the sign extension of source registers, MULT
and MULTU are identical (as are DMULT and DMULTU).

Suggested-by: Richard Henderson <richard.henderson@linaro.org>
Signed-off-by: Philippe Mathieu-Daudé <philmd@linaro.org>
Reviewed-by: Richard Henderson <richard.henderson@linaro.org>
Signed-off-by: Philippe Mathieu-Daudé <philmd@linaro.org>
---
 target/mips/tcg/translate.c | 2 --
 1 file changed, 2 deletions(-)

diff --git a/target/mips/tcg/translate.c b/target/mips/tcg/translate.c
index 6c881af5618..6d7e913263e 100644
--- a/target/mips/tcg/translate.c
+++ b/target/mips/tcg/translate.c
@@ -3615,8 +3615,6 @@ static void gen_loongson_integer(DisasContext *ctx, uint32_t opc,
         break;
     case OPC_MULTU_G_2E:
     case OPC_MULTU_G_2F:
-        tcg_gen_ext32u_tl(t0, t0);
-        tcg_gen_ext32u_tl(t1, t1);
         tcg_gen_mul_tl(cpu_gpr[rd], t0, t1);
         tcg_gen_ext32s_tl(cpu_gpr[rd], cpu_gpr[rd]);
         break;
-- 
2.45.2