From: "Justin Terry (VM) via Qemu-devel" <qemu-devel@nongnu.org>

The code already is holding the qemu_mutex for the IO thread. We do not need
to additionally take the lock again in this case.

Signed-off-by: Justin Terry (VM) <juterry@microsoft.com>
Message-Id: <1519665216-1078-5-git-send-email-juterry@microsoft.com>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
Signed-off-by: Justin Terry (VM) via Qemu-devel <qemu-devel@nongnu.org>
---
 target/i386/whpx-all.c | 2 --
 1 file changed, 2 deletions(-)

diff --git a/target/i386/whpx-all.c b/target/i386/whpx-all.c
index 14ea732..74a8f4d 100644
--- a/target/i386/whpx-all.c
+++ b/target/i386/whpx-all.c
@@ -705,9 +705,7 @@ static void whpx_vcpu_pre_run(CPUState *cpu)
             new_int.InterruptionVector = 2;
         }
         if (cpu->interrupt_request & CPU_INTERRUPT_SMI) {
-            qemu_mutex_lock_iothread();
             cpu->interrupt_request &= ~CPU_INTERRUPT_SMI;
-            qemu_mutex_unlock_iothread();
         }
     }
 
-- 
1.8.3.1